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2 years ago

9

At the beginning of 2012 Jacobs savings account had 675.20

1 answer:

OLEGan [10]2 years ago

7 0

Thanks for the update but uh... Is there a question? If you could comment the options on my reply that would be great.

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What is the solution to -1/6 + (-3/7)

BartSMP [9]

Answer:

-25/42

Step-by-step explanation:

4 0

2 years ago

Tetsuo's savings account has a balance of $1192. After 22 years, what will the amount of interest be at 1.5% compounded annually

Bess [88]

I think C is the answer

5 0

3 years ago

Read 2 more answers

4) Allison practices her violin for at least 12 hours per week. She practices for three fourths of an hour each

zaharov [31]

Answer:

12

Step-by-step explanation:

So, she practices 12 hrs per week, and already has practiced 3 hrs this week.

This means she has 9 hrs left to practice.

3/4 of an hour is one session, so to find out the number of sessions she needs, you have to do (9 hours)/(one session)

which is basically 9 / ( 3/4)

$\frac{9}{3/4}=\frac{9}{1} / \frac{3}{4} = \frac{9}{1} * \frac{4}{3} = \frac{36}{3} = 12$

She needs 12 more sessions.

7 0

2 years ago

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In March, the Chang’s phone and water bills together cost $540. If the phone cost four times as much as the water, how much was

Charra [1.4K]

The water bill was 1/5 of the total, so was 0.2*$540 = $108.

6 0

3 years ago

Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5.

Elena-2011 [213]

Answer:

$B - A = -6$

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

$x + 3y = -5$

Subtract x from both sides

$x - x + 3y = -5 - x$

$3y = -5 - x$

Divide both sides by 3

$\frac{3y}{3} = -\frac{5}{3} - \frac{x}{3}$

$y = -\frac{5}{3} - \frac{x}{3}$

The slope of the line is the coefficient of x

Slope = $- \frac{1}{3}$

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of $- \frac{1}{3}$

Having calculated the slope, next is to calculate the equation of the line using the following formula;

$m = \frac{y - y_1}{x - x_1}$

Where m is the slope; m = $- \frac{1}{3}$ ; $(x_1, y_1) = (-7,2)$

Substitute these values in the formula above; the formula becomes

$-\frac{1}{3} = \frac{y - 2}{x - -7}$

$-\frac{1}{3} = \frac{y - 2}{x +7}$

Cross Multiply

$-1(x+7) = 3(y-2)$

Open brackets

$-x - 7 = 3y - 6$

Add x to both sides

$x - x - 7 = 3y - 6 + x$

$-7 = 3y - 6 +x$

Add 6 to both sides

$-7 + 6 = 3y -6 + 6 + x$

$-1 = 3y + x$

Multipby both sides by -3

$-3(-1) = -3(3y + x)$

$3 = -9y - 3x$

$-9y - 3x = 3$

$-3x - 9y = 3$

Comparing the above to Ax + By = 3

$Ax = -3x\\A = -3$

$By = -9y\\B = -9$

$B - A = -9 - (-3)$

$B - A = -9 + 3$

$B - A = -6$

3 0

3 years ago