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Darya [45]
3 years ago
10

Which of the following would eliminate the variable on the left side of the given equation? 36 - 19w = -6w + 41.  1. add -19w  2

.  add 6w  3.  add 19w  4.  add -36
Mathematics
1 answer:
Paladinen [302]3 years ago
5 0
W=5/13 you just eliminate the negative sign
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3 years ago
Using b=1+r, what does b=
alisha [4.7K]

Answer:

Adding 12 to the circle area is equal to the square area.

Or

s2 = 12 + A

Where

s = side of square

A = area of circle

So

s2 = 12 + 36

s2 = 48

Solve this for s to get the side length

4 0
3 years ago
Can I conclude ? (Please don’t be wrong I’ll give brainlist)
Crazy boy [7]
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4 0
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Read 2 more answers
Which is better: having a stock that goes up 30% on Wednesday than drops 20% on Thursday, or a stock
finlep [7]

Step-by-step explanation:

  • If the stock goes up 30%, it's multiplied by 1.3.

The reason is that  x + .3 \times x=1.3\times x

  • If the stock goes down 20%, it's multiplied by 0.8

The reason is that x - .2 \times x = 0.8 \times x

  • If the stock goes down 30%, it's multiplied by 0.7

The reason is that x - .3 \times x = 0.7 \times x

  • If the stock goes up 40%, it's multiplied by 1.4.

The reason is that  x + .4 \times x=1.4\times x

So

If you increase it by 30% and then drop it by 20%, it means you are multiplying it by 1.3 and then multiplying it by .8. In other words:

1.3 \times 0.8=1.04

So, the net gain is = .04

Assume the original value = 500

Increase it by 30% and it becomes 650

Decrease 650 by 20% and it becomes 520

So, the net gain = 20

Verification:

500 \times .04=20

And

If you drop it by 30% and then increase it by 40%, you are multiplying it by .7 and then multiplying it by 1.4. In other words:

.7 \times 1.4=0.98

So, the net loss is = 1 - 0.98 = .02

Assume the original value = 500

Decrease it by 30% and it becomes 350.

increase 350 by 40% and it becomes 490.

So, the net loss is = 10

Verification:

500 \times .02=10

Keywords: stock, loss, gain

Learn more loss and gain from brainly.com/question/14456161

#learnwithBrainly

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =
Georgia [21]

Answer:    \dfrac{1}{2\sqrt x}

<u>Step-by-step explanation:</u>

\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}

f(x) = \sqrt x\\

f(x+h) = \sqrt{x+h}

\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}

                   =\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)

                   =\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{1}{\sqrt{x+h}+\sqrt x}

                  =\dfrac{1}{\sqrt{x+0}+\sqrt x}

                  =\dfrac{1}{2\sqrt x}

4 0
4 years ago
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