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otez555 [7]
3 years ago
12

What is 12 hours after 6:49 A.M

Mathematics
2 answers:
choli [55]3 years ago
7 0
The answer is 6:49 pm
algol [13]3 years ago
5 0
Since a day is 24 hours, and 12 hours is 1/2 of a day, 12 hours after 6:49 a.m. would be 6:49 p.m.
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If ABC~DEF what is the length of BC?<br><br> If ABC~DEF what is the length of EF?
marysya [2.9K]

BC would equal the same as EF, they are similar. All you would have to do is figure out the pre image (BC) of EF.

3 0
3 years ago
An electrician sent Bonnie an invoice in the amount of 'a' dollars for 6 hours of work that was done on Saturday. The electricia
Mazyrski [523]

Answer:

(a-f)/6 = r

Step-by-step explanation:

The total Bonnie must pay is the weekend fee plus the hourly rate times the hours worked

Cost = weekend fee * hourly rate* hours

hours = 6

weekend fee =f

hourly rate = r

Cost = a dollars

Substituting in what we know

a = f+ 6r

We want to solve for r

Subtract f from each side

a-f =f-f +6r

a-f = 6r

Divide each side by 6

(a-f)/6 = 6r/6

(a-f)/6 = r

4 0
3 years ago
The sales tax in your city is 4.4%, and an item costs $3
Aloiza [94]

Answer:

We would pay $.13  or 13 cents

Step-by-step explanation:

To find the tax on an item, multiply the amount by the tax rate

tax =3 * 4.4%

Change to a decimal form

    = 3 *.044

     =.132

We round to the nearest cent

     =.13

We would pay $.13  or 13 cents

7 0
3 years ago
Given the equation y=12x, x representing number of hours worked, y representing amount of money earned, how much would John earn
JulijaS [17]

9514 1404 393

Answer:

  72

Step-by-step explanation:

Substitute 6 for x in the equation and do the arithmetic.

  y = 12x

  y = 12·6 = 72

John earns 72 money units in 6 hours.

8 0
3 years ago
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
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