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2 years ago

F(1) =3 and f (n+1)= f(n)^2+3 then find the value of f(4)

Mathematics

1 answer:

Tcecarenko [31]2 years ago

6 0

Answer:

f(4) = 1612

Step-by-step explanation:

using the recursive formula and f(1) = 3 , then

f(2) = f(1)² + 3 = 3² + 3 = 9 + 3 = 12

f(3) = f(2)² + 3 = 144 + 3 = 147

f(4) = f(3)² + 3 = 147² + 3 = 1609 + 3 = 1612

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