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Svetllana [295]
3 years ago
8

Find the sine of both angle A and angle B.

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0
Sin = opposite/hyp

Sin A = 10/26   = 5/13

Sin b = 24/26 = 12/13

The answer is option A

Hope this helps



nalin [4]3 years ago
4 0

Answer:

The correct option is A.

Step-by-step explanation:

Let the third vertex of the triangle be C and the angle C is 90 degree.

In a right angles triangle, the sine ratio is defined as

\sin \theta=\frac{perpendicular}{hypotenuse}=\frac{opposite}{hypotenuse}

Using sine ratio,

\sin A=\frac{BC}{AB}

\sin A=\frac{10}{26}

\sin A=\frac{5}{13}

\sin B=\frac{AC}{AB}

\sin B=\frac{24}{26}

\sin B=\frac{12}{13}

Since \sin A=\frac{5}{13} and \sin B=\frac{12}{13}, therefore the correct option is A.

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