Tan9−tan27−tan63−tan81
tan9+tan81−tan27−tan63
sin9/cos9+sin81/cos81−sin27/cos27−sin63/cos63
sin90/cos81cos9−sin90/cos63cos27
1/sin9cos9−1/sin27cos27
2/sin18−2/sin54
(2)sin54−sin18/sin18sin54
4cos36sin18/sin18cos36=4
Answer:
i think its 10cm
Step-by-step explanation: brainlyest plz :)
90+80=170
180-170=10
Answer:
(-2+-5) equals -7.
Because the signs are the same, we dont change it.
(3+5) equals 8. Same like the other equation, the signs are the same so we do not change it.
Now we do (-7+8) The answer will be 1. Lets use a little graph since its hard to explain.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8
Mark -7 anyway you want. (Circle it, draw a line under it, what ever you want.)
Now Move the line 8 times.
When you do that your line will stop at 1.
And thats how you do it.
Step-by-step explanation:
Answer: $52.50
Step-by-step explanation:
1 way : 15 divided by 2 then multipy your answer by 7
2nd way : 15x7. Once you get that answer divide it by 2 to get $52.50
Answer:
A. Orthocenter
Step-by-step explanation:
In the given triangle, ΔWKS, the drawing shown the construction of a perpendicular line to the side KS that pass through the vertex <em>W </em>of ΔWKS. Therefore, the completed construction gives an altitude of the triangle ΔWKS
Repeating the same procedure from the vertex <em>S</em> to construct the perpendicular line (altitude) to the side WK, and from the vertex <em>K</em> the perpendicular line (altitude) to the side WS gives the three altitudes of the triangle
The point of intersection (the point of concurrency) of the three altitudes is the <em>orthocenter </em>of the triangle and the drawing would therefore be a step in finding the <em>orthocenter </em>of a triangle.
