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2 years ago

HELP ME WHICH ANSWER

Mathematics

2 answers:

SIZIF [17.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

30 : 13 = 30/13

Luden [163]2 years ago

8 0

Answer:

The answer is 13:30

Step-by-step explanation:

All you have to do is make sure that you put the ice skating fist because that is the one that the question mentioned first. Hope this helps :)

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Find the distance between the points (0,2)and (-5,-9)The answer must be a whole number or a fully simplified radical expression

LiRa [457]

Answer:

d = $\sqrt{146}$

Step-by-step explanation:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(-5-0)^2+(-9-2)^2}\\d= \sqrt{(-5)^2+(-11)^2}\\d= \sqrt{25+121}\\d= \sqrt{146}$

7 0

3 years ago

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

AnnyKZ [126]

Answer:

A) $5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5}$ (Yes. It has a value between zero and one.)

B) $\frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147$ (No. It does not have a value between zero and one.)

C) $\left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}$ . (Yes. It has a value between zero and one.)

D) $\frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49}$ (Yes. It has a value between zero and one.)

4 0

3 years ago

Read 2 more answers

Consider a single spin of the spinner.

alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0

3 years ago

Read 2 more answers

Suppose you roll two dice. find the probability of rolling a sum of 11.

stiv31 [10]

Answer:

1/18

Step-by-step explanation:

There are 36 different possible combinations. There are only two ways of rolling a sum of 11.

2/36 = 1/18

5 0

3 years ago

Figure A

Amiraneli [1.4K]

<h2>Answer:</h2>

Figure B

<h2>Step-by-step explanation:</h2>

The Pythagorean Theorem is $a^2 + b^2 = c^2$ , where c is the longest side of the triangle (the hypotenuse).

To find the side length of each square, you have to square root the area of each square. This means that Figure A has side lengths of 3, 6 and 8 units. Figure B has side lengths of 5, 12 and 13 units.

In Figure A, if the triangle is right-angled, the equation $3^2 + 6^2 = 8^2$ must be correct. 9 + 36 = 45. 45 is not equal to 64, so the triangle is not right-angled.

In Figure B, if the triangle is right-angled, the equation $5^2 + 12 ^2 = 13^2$ must be correct. 25 + 144 = 169. 169 is 13 squared, so the triangle is right-angled.

Alternatively, as you are already given the square values for each side length, there is no need to square root and square again. You can just test if the two smaller areas equal the larger area, but the explanation above uses a more detailed example of the Pythagorean Theorem.

8 0

2 years ago

Read 2 more answers