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Bas_tet [7]
4 years ago
14

Building on the Essential Question Howcan I intrepet tge remainder?

Mathematics
1 answer:
belka [17]4 years ago
4 0
"You can divide to find the number of minivans. There are different ways to interpret the remainder of a problem. *Answer where you add 1 to the quotient."
You might be interested in
Ricky needs 3 1/4 cups of sugar to make candy. He already has 2 1/2 cups. How many more cups of sugar does he need?
jasenka [17]
You would need to subtract the current amount from the total amount.
3 1/4 - 2 1/2
5 0
4 years ago
What is 290 divided by 375.
avanturin [10]
Your answer would be 58/75 or in decimal <span>0.77333333333

Hope that helps!
~Take care!~ :-3</span>
4 0
3 years ago
Abigail is putting tiles on a table top. She needs 48 tiles for each of 8 rows. Each row will have 6 white tiles.
almond37 [142]
I think its like this 
each row has 6 white tiles
8 rows = 48 tiles 
48 - 6 = 42
42 x 8 = 336
so 8 rows = 6 white tiles and 42 purple tiles to make 48 tiles so she will need 336 more tiles to make each 8 rows have 48 tiles

hope this helps : )
8 0
3 years ago
The Cat is a high-speed catamaran auto ferry that operates between City A and City B. The Cat can make the in about 3.5 hours at
Rama09 [41]

Answer:

196

Step-by-step explanation:

56*3.5=196

plz mark as brainliest

7 0
3 years ago
Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>​
Ksju [112]

Step-by-step explanation:

(\sec A - \csc A)(1 + \cot A + \tan A)

=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)

=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)

=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)

=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)

=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}

=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}

=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}

=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}

=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)

=\sec^2A\csc A -  \csc^2A\sec A

5 0
3 years ago
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