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iVinArrow [24]
3 years ago
8

Find x so that m || n.

Mathematics
1 answer:
Nady [450]3 years ago
8 0
M and n are parallel
so  3x -14 = 2x +25
      3x - 2x = 25 + 14
      x = 39

<span>the value of x = 39 will make both these angles equal.
3(39) -14 = 117 - 14= 103
2(39) + 25 = 78 + 25 = 103

Answer x = 39</span>

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Computing growth rates (I): Suppose Xt=(1.04)^t and Yt=(1.02)^tCalculate the growth rate of Zt in each of the following cases:(a
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Answer:

z(t) = (0.9808)^t

z(t) = (1.0196)^t

z(t) = (0.9808)^t

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Step-by-step explanation:

We are given the following in the question:

x(t)=(1.04)^t\\y(t)t=(1.02)^t

We have to find the growth rate z(t) in each of the following cases:

(a) z = xy

z(t) = x(t)y(t)\\z(t) = (1.04)^t.(1.02)^t\\z(t) = (1.04\times 1.02)^t\\z(t) = (1.0608)^t

(b) z=x/y

z(t) =\displaystyle\frac{x(t)}{y(t)}\\\\z(t) = \frac{(1.04)^t}{(1.02)^t} = \bigg(\frac{1.04}{1.02}\bigg)^t\\\\z(t) = (1.0196)^t

(c) z=y/x

z(t) =\displaystyle\frac{y(t)}{x(t)}\\\\z(t) = \frac{(1.02)^t}{(1.04)^t} = \bigg(\frac{1.02}{1.04}\bigg)^t\\\\z(t) = (0.9808)^t

(d) z=x^(1/2) y^(1/2)

z(t) = (x(t))^{\frac{1}{2}}(y(t))^{\frac{1}{2}}\\z(t) = ((1.04)^t)^\frac{1}{2} ((1.02)^t)^\frac{1}{2}\\z(t) = (1.0608)^{\frac{t}{2}}\\z(t) = (1.03)^t

(e) z=(x/y)^2

z(t) =\bigg(\displaystyle\frac{x(t)}{y(t)}\bigg)^2\\\\z(t) =\bigg( \frac{(1.04)^t}{(1.02)^t}\bigg)^2 = \bigg(\frac{1.04}{1.02}\bigg)^{2t}\\\\z(t) = (1.0404)^t

(f) z=x^(-1/3)y^(2/3)

z(t) = (x(t))^{\frac{-1}{3}}(y(t))^{\frac{2}{3}}\\z(t) = ((1.04)^t)^{\frac{-1}{3}}((1.02)^t)^{\frac{2}{3}}\\z(t) = ((1.04)^{\frac{-1}{3}})^t((1.02)^{\frac{2}{3}})^t\\z(t) = (1.04^{\frac{-1}{3}}\times 1.02^{\frac{2}{3}})^t\\z(t) = (1.0001)^t

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