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3 years ago

Which polynomial identity will prove that 65 = 81 - 16

Mathematics

1 answer:

steposvetlana [31]3 years ago

8 0

9^2 - 4^2 = (9 + 4)(9 - 4)
So the polynomial identity used here is
$(x + y)(x - y) = {x}^{2} - {y}^{2}$

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It took you 120 minutes to work 15 math problems. How long did you spend on each problem

Karolina [17]

Answer:

8 minutes

Step-by-step explanation:

120÷ 15= 8

yup thats pretty much it

5 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!! Subract and simplify.

pantera1 [17]

Answer: C

Step-by-step explanation:

$\dfrac{x+1}{x-5} - \dfrac{x-2}{x+3}$

= $\dfrac{x+1}{x-5}(\dfrac{x+3}{x+3}) - \dfrac{x-2}{x+3}(\dfrac{x-5}{x-5})$

= $\dfrac{x^{2}+4x+3}{(x-5)(x+3)} - \dfrac{x^{2}-7x+10}{(x-5)(x+3)}$

= $\dfrac{x^{2}+4x+3-(x^{2}-7x+10)}{(x-5)(x+3)}$

= $\dfrac{11x-7}{(x-5)(x+3)}$

5 0

3 years ago

4y= -6x +8 find the y-intercept

ivanzaharov [21]

First, divide each side by 4 to get y alone on the left side.

y=-6/4x+2

The y intercept is 2

7 0

4 years ago

A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

4 years ago

Help! Got it wrong after trying first time and need helppp !

finlep [7]

We are given the equation:

DA - 2qA = B³

Taking 'A' common on the LHS

A(D - 2q) = B³

Dividing both sides by (D - 2q)

A = B³ / (D - 2q)

5 0

3 years ago