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4 years ago

Do glaciers move materials long distance

1 answer:

5 0

Yes. Glaciers typically are used to name ice that are extremely large in size, and generally can survive great distances from their origin points. These large glaciers can support materials, and can be like a moving island.

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Write the point which should be taken while making economic plan

taurus [48]

The most cherished elements involved in a good plan are as under:
(i) Definite Objective:
(ii) Central Planning Authority:
(iii) Democratic Character:
(iv) Only an Advisory Role of Planning Commission:
(v) Comprehensiveness:
(vi) Planning for Consumption:
(vii) Rational Allocation of Resources

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3 years ago

“FAKE SPECIALIST” YAN LIMENG

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Answer:

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3 years ago

Which is most likely an example of point source pollution?

malfutka [58]

Answer:

smokestacks, discharge pipes, drainage ditches.

Explanation:

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3 years ago

a farmer who has grown corn for the past five years notices in the sixth year that his harvest is significantly smaller, despite

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4 years ago

Read 2 more answers

While pulling a bicycle out of the garage, you must pull it a total of 17 m with a force of 27 N. How much work are you doing on

RSB [31]

<h2>Answer:</h2>

The Work $W$ done by a Force $F$ refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.

It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule. Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:

$1J=(1N)(1m)=Nm$

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:

$W=(F)(d)$ (1)

When they are not parallel, both directions form an angle, let's call it $\alpha$ . In that case the expression to calculate the Work is:

$W=Fdcos{\alpha}$ (2)

For example, in order to pull the bicycle out of the garage, you have to apply a force along the distance $d$ to overcome the resistance of the weight of the bicycle.

In this case both (the force and the distance in the path) are parallel, so the work $W$ performed is the product of the force $F$ by the distance traveled $d$ , as shown in equation (1).

Hence:

$W=(27N)(17m)$

$W=459Nm=459J$ >>>>This is the work

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3 years ago