All categories

3 years ago

(x1/6)3 simplify the expression

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

7 0

For this case we have the following expression:

$(x ^ {\frac {1} {6}}) ^ 3$

We have that by definition of properties of powers it is fulfilled that:

$(a ^ n) ^ m = a ^ {n * m}$

Now we have to, by applying the property:

$(x ^ {\frac {1} {6}}) ^ 3 = x ^ {\frac {3} {6}}$

Simplifying:

$x ^ {\frac {3} {6}} = x ^ {\frac {1} {2}}$

Answer:

$x ^ {\frac {1} {2}}$

svp [43]3 years ago

6 0

Answer:

x1/2

Step-by-step explanation:

Simplify the following:

(3 x1)/6

Hint: | In (x1×3)/6, divide 6 in the denominator by 3 in the numerator.

3/6 = 3/(3×2) = 1/2:

Answer: x1/2

You might be interested in

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

$\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]$

The left and right endpoints of the $i$ -th subinterval, respectively, are

$\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8$

$r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8$

for $1\le i\le4$ , and the respective midpoints are

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8$

Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

$T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}$

Midpoint rule

We approximate the area for each subinterval by

$M_i=f(m_i)(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}$

Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial $p_i(x)$ , where

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It so happens that the integral of $p_i(x)$ reduces nicely to the form you're probably more familiar with,

$S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))$

Then the integral is approximately

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}$

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0

3 years ago

11 3/4-7 1/4 evaluate answer need asap

Debora [2.8K]

Answer:

−6

Step-by-step explanation:

8 0

3 years ago

If 5.90 × 1.8 = 10.62, what does 106.2 ÷ 59 equal?

alexira [117]

Answer:

1.8

Step-by-step explanation:

- hope this helps!!

8 0

3 years ago

Read 2 more answers

Find the common difference of the arithmetic sequence -6, 2, 10

Butoxors [25]

Step-by-step explanation:

-6+8=2 by -6 will cut from 8 and remain 2.

2+8=10 by same way 8 will added to 2 and got 10.

I hope it will help you

7 0

3 years ago

A marker is 0.13 what is the length in millimeters

Flura [38]

If the marker is 0.13cm, then it is 13 millimeters.

5 0

3 years ago