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3 years ago

Is anyone willing to help me with this? I tried adding this and still no answer. Please help..

Mathematics

1 answer:

GaryK [48]3 years ago

3 0

Answer: C. (-4, -2)

Step-by-step explanation:

First, eliminate one of the variables and solve for the remaining variable:

2x - 5y = 2 → 3(2x - 5y = 2) → 6x - 15y = 6

3x + 2y = -16 → -2(3x + 2y = -16) → -6x - 4y = 32

-19y = 38

y = -2

Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

2x - 5(-2) = 2

2x + 10 = 2

2x = -8

x = -4

x = -4, y = -2

Check:

Plug in the x- and y-values into the other original equation:

3x + 2y = -16

3(-4) + 2(-2) = -16

-12 + -4 = -16

-16 = -16 $\checkmark$

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