Answer:
Step-by-step explanation:
False (APEX)
Answer:
you need to ask one bye one. easyer for us
Answer:
<em>The salesperson's commission for this month is $3,803</em>
Step-by-step explanation:
<u>Percentages</u>
Let's call x to the sales volume, not including commission.
The salesperson is paid an 8.25% commission on sales, thus the total invoice is x + 8.25%x = x + 0.0825x = 1.0825x
We are given this total invoice, thus:
1.0825x = $49,900
Dividing by 1.0825:
x = $46,097
The salesperson's commission is
0.0825*$46,097=$3,803
The salesperson's commission for this month is $3,803
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
Yes they are directly proportional quantities.
Step-by-step explanation:
We find the area of a square by;
A = length squared or (L)² , where 'L' stands for length and 'A' stands for area.
So Area = L²
Assume the length is a units and increase the length by 2 units
The initial area before increasing the length is a²
After increasing the length, the area becomes: (a + 2)² = a² + 4a + 4
Now we subtract the initial area from the final area and get;
(a² + 4a + 4) - a² = 4a + 4
So the new area increases by 4a + 4 units.
Hence, the area increases as the length increases implying that the area of a square is directly proportional to its length.
We denote this proportionality as;
A ∝ L