Put it in the form
ax^2 + bx + c = 0
use the quadratic formula
x = [ -b + sqrt( b^2 - 4 ac ) ] / 2a
x = [ -b - sqrt( b^2 - 4 ac ) ] / 2a
7v^2 - 7v - 22 = 0
a = 7
b = -7
c = -22
v = [ 7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = 2.34
v = [ 7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = -1.34
An asexual structure where spores develop is Sporangium
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
The formula for the lateral surface area of a right circular cone is:

where r is the radius of the base, and l is the slant height.
Plugging in the values we get:
Answer:
Step-by-step explanation: