A =
5 and -5
-1 and 3
¹/₃B =
-6 and 12
-7 and 7
¹/₃B + A =
-1 and 7
-8 and 10
To solve this problem, you must follow the proccedure below:
1. T<span>he block was cube-shaped with side lengths of 9 inches and to calculate its volume (V1), you must apply the following formula:
V1=s</span>³
<span>
s is the side of the cube (s=9)
2. Therefore, you have:
V1=s</span>³
V1=(9 inches)³
V1=729 inches³
<span>
3. The lengths of the sides of the hole is 3 inches. Therefore, you must calculate its volume (V2) by applying the formula for calculate the volume of a rectangular prism:
V2=LxWxH
L is the length (L=3 inches).
W is the width (W=3 inches).
H is the heigth (H=9 inches).
4. Therefore, you have:
V2=(3 inches)(3 inches)(9 inches)
V2=81 inches
</span><span>
5. The amount of wood that was left after the hole was cut out, is:
</span>
Vt=V1-V2
Vt=648 inches³
Answer: -5.428
Step-by-step explanation:
33 + 5 + 7z = 0
38 + 7z = 0
7z = -38
z = -38/7
-(-5 - 6x) = 4 (5x +3)
Pretend that there is a -1 in front of the first bracket
-1(-5-6x)= 4(5x+3)
Mutiply the first bracket by -1
(-1)(-5)(-1)(-6x)= 5+6x
Mutiply the second bracket by 4
(4)(5x)(4)(3)= 20x+12
5+6x= 20x+12
move 20x to the other side
5+6x-20x= 20x-20x+12
5+6x-20x= 12
5-14x= 12
move 5 to the other side
sign changes from +5 to -5.
5-5-14x= 12-5
-14x=7
divide by -14
-14x/-14= 7/-14
x= -1/2
Answer: x= -1/2
25 is the answer to question 4 traveld by a passenger in one full rotation
