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Snowcat [4.5K]
3 years ago
6

70.2 x 10 6.702 x 10? 7.02 x 100 7.02 x 10?

Mathematics
2 answers:
vovikov84 [41]3 years ago
6 0
70.2 x 10= 702

6.702 x 10= 67.02

7.02 x 100= 702

7.02 x 10= 70.2
Orlov [11]3 years ago
3 0

Answer:

70.2 x 10=702.

6.702 x 10=67.02

7.02 x 100=70.2

7.02 x 10=70.2

Step-by-step explanation:

I hope this help! :)

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Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
  • -u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

  (6 -u)/(u +2)

__

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

  8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

__

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

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4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

7 0
3 years ago
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
Choose the best reason for using the median as the measure of central tendency.
Alchen [17]

Answer:

The median is usually preferred in these situations because the value of the mean can be distorted by the outliers. However, it will depend on how influential the outliers are. If they do not significantly distort the mean, using the mean as the measure of central tendency will usually be preferred.

6 0
3 years ago
What is the value of x, given that OP||NQ ?
Irina-Kira [14]
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3 years ago
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gladu [14]
19,200 ! To get the surface area of the rectangular prism you have to get the area of each side. Length x Width x Sides(6 in your case).
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