Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:
velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )
acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )
Then when <em>t</em> = <em>π</em>, the particle's acceleration is
<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)
… = -5 • (-1) - 9 • 0 = 5
A triangle has three vertices and three sides.
Answer:
55
Step-by-step explanation:
3x-12=2x
+12
3x=2x +12
-2x
x=12
4(12)+ 9
48+9
=55
1/7 is your answer. It can't be reduced any further. If there is supposed to be a problem, next time, add it.
