How many numbers between 111 and 100100100 (inclusive) are divisible by 333 and 101010?

2 answers:

5 0

If the numbers that we are checking divisibility for are between 1-100, there are 3 numbers.

30, 60, and 90 are all divisible by both 3 and 10 because both 3 and 10 are factors of these 3 numbers.

Andru [333]2 years ago

4 0

How many numbers between 111 and 100100100 (inclusive) are divisible by 333 and 101010? Its 67 numbers.

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The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the

ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/ $\sqrt{n}$ )

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/ $\sqrt{n}$

The upper limit => C.I_u = μ + Z*σ/ $\sqrt{n}$

The lower limit => C.I_l = μ - Z*σ/ $\sqrt{n}$

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/ $\sqrt{n}$ )

= 200 + (1.96*30)/ $\sqrt{n}$

= 200 + 58.8/ $\sqrt{n}$

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