Answer:
-1/6 and 1 1/6
I included an image showing the points to select, in red and the point we start at, in blue.
Step-by-step explanation:
We need to get the numbers they tell us (2/3 & 1/2) to have the same denominators as the numbers on the number line before we can start.
1/2 is just the simplified form of 3/6 and 2/3 is just the simplified form of 4/6.
So 1/2 is actually 3/6 on the number line.
Now we need to find the numbers that are 2/3 (or 4/6) unit away from 3/6.
Count 4 units to the right and 4 to the left of 3/6 to get the numbers we are looking for.
These numbers are -1/6 and 1 1/6
I hope this helps!!
Lmk if u have any questions! :)
Pic is attached below.
Answer:
Step-by-step explanation:
From the given figure it is clear that the stop board is a regular hexagon and ∠I is an exterior angle of the regular hexagon.
Exterior angle of a regular polygon with n sides 
In a regular hexagon number of sides: n =6
Exterior angle of a regular hexagon 
Since ∠I is an exterior angle of the regular hexagon, therefore, 
.
4 Oranges, 310 divided by 5= 64, 64 times 4=248.
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
