since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
The scale factor from the first map to the second map can be determined by:
scale factor = (length of trail in first map) / (length of trail in second map)
8 cm / 6 cm = 1.33
The landmark on the first map is a triangle with side lengths of 3mm, 4mm, and 5mm.
3mm = 3 * 1.33 mm = 3.99mm
4mm = 4 * 1.33 mm = 5.32mm
5mm = 5 * 1.33 mm = 6.65mm
Answer:
7.
Step-by-step explanation:
If <span>(5^2-4) / (5+2) then
=(25 - 4 )/3
= 21/3
= 7
if 4/5 fraction then
</span><span>5^2-4/5+2
= 25 - 4/5 + 2
= 27 - 4/5
= 26 5/5 - 4/5
= 26 1/5
= 26.2</span>
Answer:
The answer to your question is: 4x³ - 6x² + 8x
Step-by-step explanation:
see the picture