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borishaifa [10]
3 years ago
14

Find the equation of the ellipse with the following properties.

Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0
The equation of an ellipse where the major axis 2a is greater than the minor 2b
 (x-h)²/a² + (y-k)²/b² =1.
When 2b>2a , then the equation becomes (y-h)²/b² + (x-k)²/a² =1
In our example a = 4 and b = 9. Moreover h=0 and k=0 because the center is on the origin, so the equation becomes:
y²/b² + x²/a² = y²/81 + x²/16 = 1
kaheart [24]3 years ago
5 0
Check the picture below

so.. hmm notice the center h,k and the major and minor axis components, thus just plug them in.

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Does the graph represent function?
Ilia_Sergeevich [38]

Answer:

no

Step-by-step explanation:

4 0
3 years ago
Jamal runs the bouncy house at a festival. The bouncy house can hold a maximum of 1200 pounds at one time. He
jekas [21]
Sorry I really need point but I wish you good luck!
7 0
3 years ago
Use the Quadratic Formula to solve the equation 4x^2−7=4x.
tino4ka555 [31]

Answer:

\large\boxed{x=\dfrac{1}{2}-\sqrt2\ or\ x=\dfrac{1}{2}+\sqrt2}

Step-by-step explanation:

\text{The quadratic formula of}\ ax^2+bx+c=0:\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{We have:}\\\\4x^2-7=4x\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\4x^2-4x-7=0\\\\a=4,\ b=-4,\ c=-7\\\\b^2-4ac=(-4)^2-4(4)(-7)=16+112=128\\\\\sqrt{b^2-4ac}=\sqrt{128}=\sqrt{64\cdot2}=\sqrt{64}\cdot\sqrt2=8\sqrt2\\\\x=\dfrac{-(-4)\pm8\sqrt2}{(2)(4)}=\dfrac{4\pm8\sqrt2}{8}\qquad\text{simplify by 4}\\\\x=\dfrac{1\pm2\sqrt2}{2}\to x=\dfrac{1}{2}\pm\sqrt2

6 0
3 years ago
Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]
True [87]

Answer:

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Step-by-step explanation:

The inverse of a square matrix A is A^{-1} such that

A A^{-1}=I where I is the identity matrix.

Consider, A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]

\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}

\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0

\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}

=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc

4\cdot \:6-3\cdot \:3=15

=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

Therefore, the inverse of given matrix is

=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}

4 0
4 years ago
Please answer this question now
liubo4ka [24]

Answer:

541.67m²

Step-by-step explanation:

Step 1

We find the third angle

Sum of angles in a triangle = 180°

Third angle = Angle V = 180° - (63 + 50)°

= 180° - 113°

Angle V = 67°

Step 2

Find the sides x and v

We find these sides using the sine rule

Sine rule or Rule of Sines =

a/ sin A = b/ Sin B

Hence for triangle VWX

v/ sin V = w/ sin W = x / sin X

We have the following values

Angle X = 50°

Angle W = 63°

Angle V = 67°

We are given side w = 37m

Finding side v

v/ sin V = w/ sin W

v/ sin 67 = 37/sin 63

Cross Multiply

sin 67 × 37 = v × sin 63

v = sin 67 × 37/sin 63

v = 38.22495m

Finding side x

x / sin X= w/ sin W

x/ sin 50 = 37/sin 63

Cross Multiply

sin 50 × 37 = v × sin 63

x = sin 50 × 37/sin 63

x = 31.81082m

To find the area of triangle VWX

We use heron formula

= √s(s - v) (s - w) (s - x)

Where S = v + w + x/ 2

s = (38.22 + 37 + 31.81)/2

s = 53.515

Area of the triangle = √53.515× (53.515 - 38.22) × (53.515 - 37 ) × (53.515 - 31.81)

Area of the triangle = √293402.209

Area of the triangle = 541.66614164081m²

Approximately to the nearest tenth = 541.67m²

5 0
4 years ago
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