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zvonat [6]
3 years ago
5

Whats the solution of x^2+4x-4=8

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

x = 2, x = -6

Step-by-step explanation:

x^2+4x-4=8

Subtract 8 from both sides.

x^2+4x-4-8=8-8

Simplify.

x^2+4x-12=0

Solve with quadratic formula.

a = 1

b = 4

c = -12

I do not have time to show work for quadratic formula parts.

I am so sorry for this inconvenience.

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Answer:

all real numbers except ±5.

Step-by-step explanation:

Each function (f(x), g(x)) has a domain that is all real numbers. Their quotient (f(x)/g(x)) must exclude values that make g(x) = 0. The quotient is undefined when the denominator is zero. Those excluded values are x = ±5.

The domain of (f/g)(x) is all real numbers except ±5.

___

Of course you recognize x^2 -25 = 0 has solutions x = ±√25 = ±5. You can get there two ways:

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  2. factor the difference of squares and set the factors to zero: (x-5)(x+5)=0 has solutions x-5=0 and x+5=0, that is, x = ±5.
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Explain how to find the sum of 3/10 + 4/100
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Then, we must make the fractions being added all have the common denominator.

So, we must multiply 3/10 * 10/10, which equals 30/100

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Then, just add across the numerator to get 34/100, which can be simplified to 17/50

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