Answer: 16384
Step-by-step explanation:
Given, Total jars = 4
Total marbles = 7
Since we need to put marbles in 4 different jars, we need to choose a jar each time.
Possible choices for jars =4
Number of time we need to choose = number of marbles
So, by fundamental counting principle, we have
Total ways to put 7 marbles in 4 jars = ![4\times4\times 4\times 4\times4\times 4\times 4](https://tex.z-dn.net/?f=4%5Ctimes4%5Ctimes%204%5Ctimes%204%5Ctimes4%5Ctimes%204%5Ctimes%204)
![=4^7\\\\=16384](https://tex.z-dn.net/?f=%3D4%5E7%5C%5C%5C%5C%3D16384)
Hence, the required number of ways =16384
Hello,
If 3x-1>=0 then
x>=1/3
|3x-1\=3x-1
2*|3x-1|=18
2*(3x-1)=18
6x-2=18
6x=20
x=10/3
else
x<1/3
|3x-1|=-(3x-1)
2*|3x-1|=18
2(-(3x-1))=18
-6x+2=18
-6x=16
x=-8/3
endif
What are the math problems?
Answer:
I found that the answer is (5,1)
Step-by-step explanation:
4 times x(5) is 20
3 times y(1) is 3
20 + 3 = 23
bottom equation:
x(5) -- 5y(1) = 0