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3 years ago

What is 125 centimeters to 87.5 centimeters

Mathematics

2 answers:

nignag [31]3 years ago

7 0

If you are asking for the percent change, then the percent of change is a 30% decrease.

bagirrra123 [75]3 years ago

3 0

If you are asking how to subtract 125 centimeters and make it 87.5, you have to subtract from 125. The easiest way to do this is to subtract 87.5 from 125, getting 37.5. So, if you add 37.5 to 87.5, you will have 125. So, the correct answer is to subtract 37.5 to get 87.5.

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3 years ago

What is the pattern as the exponents decrease?

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3 years ago

Read 2 more answers

1. The manager of FrozonAir Refrigerator factory notices that on Monday it cost the company a total of $25,000 to build 30 refri

Vinvika [58]

Answer:

The fixed costs per day for the factory is $10,000 and marginal cost of one refrigerator for $500

Step-by-step explanation:

Let

Cost per refrigerator (marginal cost) = r

Fixed costs per day for the factory = f

Total cost = variable cost + fixed cost

Monday

25,000 = 30r + f

Tuesday

30,000 = 40r + f

Using Monday,

f = 25000 -30r

Substitute f = 25000 - 30r into Tuesday

30,000 = 40r + f

30,000 = 40r + (25,000 -30r)

30,000 = 40r + 25,000 - 30r

Collect like terms

30,000 - 25,000 = 40r - 30r

5,000 = 10r

Divide both sides by 10

r = 5,000 / 10

= 500

r = $500

Substitute r= 500 into Monday equation

f = 25,000 -30r

= 25,000 - 30(500)

= 25,000 - 15,000

= 10,000

f = $10,000

Therefore, the fixed costs per day for the factory is $10,000 and marginal cost of one refrigerator for $500

7 0

3 years ago

How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit

Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have ${13 \choose 2} = 78$ possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

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3 years ago