Answer:
The correct answer is (-5,-5)
Step-by-step explanation:
1. Both of the equations are in standard form, so first you set them equal to each other.
2. Solve for x as a normal algebraic equation.
3. Back substitute your answer for x into one of the original equations. (back substitution is just putting the x back into the equation and solving for y.)
4. Now you have your x and y coordinates, and the point of intersection of the two lines.
Answer:
Area of the remaining triangle with the villager is 1243.13 m²
Step-by-step explanation:
Triangle ABC is the triangular plot of a villager shown in the figure attached.
Sarpanch requested the villager to donate land which is 6 m wide and along the side AC which measures 132.8m.
Other sides of the plot has been given as AB = 50m and BC = 123 m.
Now area of this land before donation = 
= 
= 3075 square meter
After donation of the land the triangle formed is ΔDBE.
In ΔABC,

tan(∠ABC) = 
= 0.4065
∠ABC = 
= 22.12°
In ΔEFC,
tanC = 
0.4065 = 
CF = 
CF = 14.76 m
Since DE = AC - (CF + AG)
= 132.8 - (2×14.76)
= 132.8 - 29.52
= 102.48 m
Now in ΔDBE,
sin(∠DEB) = 
sin(22.12) = 
DB = 102.48×0.3765
= 38.59 m
Similarly, cos(22.12) = 
0.9264 = 
BE = 102.48×0.9264
= 94.94m
Now area of ΔDBE = 
= 
= 1831.87 square meter
Area of remaining triangle with the villager = Area of ΔABC - Area of ΔDBE
= 3075 - 1831.87
= 1243.13 square meter
Answer:
13
Step-by-step explanation:
See how many 5s there are in 47? There are 9 and also a leftover 2 which is your remainder.<span />
Answer:
its 4x
Step-by-step explanation: