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Stella [2.4K]
4 years ago
15

A bowling alley offers special weekly bowling rates. the weekly rates are 5 games for $15, 6 games for $17.55, 7 games for $20.1

0, and 8 games for $22.65. if this pattern continues, how much will it cost to bowl 10 games in a week?
Mathematics
2 answers:
julia-pushkina [17]4 years ago
7 0
The rates of the weekly games increases by 2.55 then in 10 games the rate will be 27.75
Triss [41]4 years ago
6 0

Answer:

Step-by-step explanation:

Given the following rates;

5 games for $15, 6 games for $17.55, 7 games for $20.10, and 8 games for $22.65

Let a be the first term = $15

d = common difference = $17.55 - $15

d = $2.55

10 games will be the 6th term given that 5 games is the first term

Using the nth term of an A.P

Tn = a + (n - 1)d

T6 = 15 + (6 - 1)2.55

T6 = 15 + 12.75

T6 = $27.75

if this pattern continues, 10 games in a week will cost $27.75

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Step-by-step explanation:

Okay so essentially the a_n is just a substitute for x.

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y=mx+b\\a_n=mn+b\\a_n=2n+13

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y=a_n\\m=2\\n=x\\b=13

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y=mx+b\\a_n=2n+13\\a_1=2(1)+13=15\\a_2=2(2)+13=17\\a_3=2(3)+13=19\\a_4=2(4)+13=21\\a_5=2(5) +13=23\\a_6=2(6)+13=25\\a_7=2(7)+13=27\\a_8=2(8) +13=29\\a_9=2(9)+13=31\\a_{10}=2(10)+13=33\\a_{11}=2(11)+13=35\\a_{12}=2(12)+13=37\\a_{13}=2(13)+13=39

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