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andreev551 [17]
3 years ago
7

What is the original price if there is a 45% discount and the sale price is $550?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Original price×(1-discount price)=new price or sale price so

Put x in original price...x(1-45/100)=550

So the original price is 1000

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Please help me :) with this math problem, it's exponential functions.
noname [10]

Answer:

f(x) = 9(5/3)^x

Step-by-step explanation:

f(x) = a(b^x)

x = 0

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9 = a

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x = 1

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f(x) = 9(5/3)^x

8 0
3 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
What is the expanded form of 3×(x+3)^2
saul85 [17]
3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x

answer
3x^3 + 18x^2 + 27x
7 0
3 years ago
Someone help me asap?
Rzqust [24]

1. 66

2. -36

3. 10

4. 1

8 0
3 years ago
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A flyer is spread by people at a large conference. Within one hour, the first person gives a stack of flyers to six people. With
Mandarinka [93]

Answer:

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6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).

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Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)

3 0
3 years ago
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