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Tju [1.3M]
4 years ago
12

John's age increased by 11 is 5 less than 5 times his age. How old is he?

Mathematics
2 answers:
astraxan [27]4 years ago
5 0
It would be 1 because u would subtract all of it
pychu [463]4 years ago
3 0
I hope this helps you




x+11=5x-5

4x=16

x=4
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How do you factor the expression 54+24= Thanks!
pychu [463]

Answer:

Step-by-step explanation:

1.The prime factorization of 54 is: 2 x 3 x 3 x 3.

2.The prime factorization of 24 is: 2 x 2 x 2 x 3.

3.The prime factors and multiplicities 54 and 24 have in common are: 2 x 3.

4.2 x 3 is the GCF of 54 and 24.

Answer: GCF(54,24) = 6.

6 0
3 years ago
Read 2 more answers
Help i really have no clue not sure where to start
Juli2301 [7.4K]

Focus on the top line angles for now.

Those two angles combine to the straight angle ABC, which is 180 degrees.

(angleABY) + (angleYBC) = angle ABC

(x+25)+(2x+50) = 180

(x+2x) + (25+50) = 180

3x+75 = 180

3x = 180-75

3x = 105

x = 105/3

x = 35

We'll use this x value to find that:

  • angle YBC = 2x+50 = 2*35+50 = 70+50 = 120 degrees
  • angle BEF = 5x-55 = 5*35-55 = 175-55 = 120 degrees

Angles YBC and BEF are corresponding angles (they are both in the northeast corner of their respective four-corner angle configuration). They are both 120 degrees. Since we have congruent corresponding angles, we have effectively proven that AC is parallel to DF. Refer to the converse of the corresponding angles theorem.

The regular version of the "corresponding angles theorem" says that if two lines are parallel, then the corresponding angles are congruent. The converse reverses the logic of the conditional statement. Meaning that if the corresponding angles are congruent, then the lines are parallel.

6 0
2 years ago
Read 2 more answers
A line passing (a,3) and (5,5) is perpendicular to a line passing through (0,0) and (1,a) Find the value of a.
vodka [1.7K]

Answer:

a = -5

Step-by-step explanation:

(5 - 3)/(5 - a)

2/(5 - a)

perpendicular of 2/(5 - a) = -(5 - a)/2

(a - 0)/(1 - 0) = -(5 - a)/2

a/1 = -(5 - a)/2

2a = -5 + a

a = -5

6 0
4 years ago
Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2
Talja [164]

Given:

The given equation is

y-3=(2-x)^2

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

y-k=a(x-h)^2     ...(i)

where, (h,k) is vertex, \left(h,k+\dfrac{1}{4a}\right) and directrix is y=k-\dfrac{1}{4a}

We have,

y-3=(2-x)^2

It can be written as

y-3=(-(x-2))^2

y-3=(x-2)^2    ...(ii)

On comparing (i) and (ii), we get

h=2,k=3,a=1

Vertex of the parabola is (2,3).

Focus=\left(2,3+\dfrac{1}{4(1)}\right)

Focus=\left(2,3+\dfrac{1}{4}\right)

Focus=\left(2,\dfrac{13}{4}\right)

Therefore, the focus of the parabola is \left(2,\dfrac{13}{4}\right).

Directrix of the parabola is

y=3-\dfrac{1}{4(1)}

y=3-\dfrac{1}{4}

y=\dfrac{11}{4}

Therefore, the directrix of the parabola is y=\dfrac{11}{4}.

4 0
3 years ago
8(p + 5) = 24 solve for p.
PilotLPTM [1.2K]
P= -2 hope this helps :)
4 0
3 years ago
Read 2 more answers
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