In order to solve this problem, lets take the two terms in the binomial (4x and -3) and, for each one, multiply them by each term in the trinomial (2x^2, -7x, and 1):

$(4x-3)(2x^{2}-7x+1)$

$(4x*2x^{2})+(4x*-7x)+(4x*1)+(-3*2x^{2})+(-3*-7x)+(-3*1)$

$8x^{3}+(-28x^{2})+4x+(-6x^{2})+21x+(-3)\\$

$8x^{3}-28x^{2}+4x-6x^{2}+21x-3$

Let's combine like terms to get our final answer:

$8x^{3}-28x^{2}-6x^{2}+4x+21x-3$

$8x^{3}-34x^{2}+25x-3$

6 0

3 years ago

2 more than 5 groups of 3

Anvisha [2.4K]

5*3+2 = 15+2 = 17
The asnwer is 17.

5 0

4 years ago

Sarah's family of 4 went camping for 1 week. they each year 3 paper plates a day. how many paper plates did the family use up we

Mama L [17]

Answer:

Step-by-step explanation:

they use 3 plates a day

there are 4 of them

so in one day, they use 12 plates [3x4]

they camp for 7 days, so 12x7.

84!! :D

4 0

3 years ago