1 would be B. 2 would be a
Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:
What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So
has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79
Answer:
Step-by-step explanation:
• AB, BC, and AC form a triangle. Enter a possible value of AC....
So it asks for only a possible value of AC as there are many possible values.
Given AB = 8 cm and BC = 6 cm, they are in the ratio of 3:4.
Line segments of 3, 4 and 5 length will form a right-angled triange.
A possible value of AC = 5*2 = 10cm
• Points A, B, and C lie on the same line, and C lies between A and B.
So AC+CB = AB
AC+6 = 8
AC = 2cm
Enter this value of AC in the second
response box.
In the graph you can see the point are crossing Y -1 and x= 2,
x-y=xy
2-1=1
Y=1
Answer:
0.942
Step-by-step explanation:
Multiply the normal way as if there were no decimals, then move the decimal 3 times to the left.