The probability of a randomly selected hard drive from the company lasting between 2 years 3 months and 3 years 3 months is 32.22%
Given here,
Mean (μ) = 3 years 6 months
= (3×12)+6 = 42 months
Standard deviation (σ) = 9 months
We will find the z-score using the formula: z = (X - μ)/σ
Here X₁ = 2 years 3 months
= (2×12)+3 = 27 months
and X₂ = 3 years 3 months
= (3×12)+3 = 39 months
So, z (X₁ =27) = 
and z (X₂ =39) = 
According to the standard normal table,
P(z> -1.666...) = 0.0485 and P(z< -0.333...) = 0.3707
So, P(27 < X < 39)
= 0.3707 - 0.0485
= 0.3222
= 32.22 % [Multiplying by 100 for getting percentage]
So, the probability of a randomly selected hard drive from the company lasting between 2 years 3 months and 3 years 3 months is 32.22%
Answer:
ln(2) + 3ln(a) - 4ln (b)
Step-by-step explanation:
ln(2a^3 /b^4)
We know that ln(x/y) = ln (x) - ln y
ln(2a^3 ) - ln (b^4)
We know that ln (xy) = ln x + ln y
ln(2) + ln(a^3 ) - ln (b^4)
We know that ln(x^y) = y ln (x)
ln(2) + 3ln(a) - 4ln (b)
Answer:
200
Step-by-step explanation:
Answer:
20%
Step-by-step explanation:
1.92 - 1.60 = 0.32
percentage increase = (0.32/1.60) * 100 =
0.2 * 100 = 20%
Answer:
y = 20.922
Step-by-step explanation:
Simply plug in <em>x</em> and evaluate:
y = 15 + 3ln(7.2)
Only way to calculate ln is to plug into a calc:
We should get 20.9222 as our answer.