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3 years ago

14

Tanya has a garden with a trench around it. The garden is a rectangle with length 2 1/2 meters and a width of 2 meters. The tren

ch and garden together make a rectangle with length of 3 1/2 meters and a width of 3 meters.
Find the area of just the trench

1 answer:

fenix001 [56]3 years ago

5 0

You need a height measurement in order to find the area.

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A culture of bacteria doubles every hour. If there are 500 bacteria at the beginning, how many bacteria will there be after 24 h

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<span>8388608000. you will have to keep multiplying 2 24 times.</span>

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3 years ago

Mr. Brown owned a house, which he rented for $60 a month. The house was assessed at $9000. In 1975 the rate of taxation was incr

Alexandra [31]

We first calculate the percentage increase on the tax

Old value = 25×9 = 225 ⇒ The value 9 represents the 9 lots of thousands of the house's value
New value = 28×9 = 252

Increase in tax = 252 - 225 =27
Percentage increase = (27÷225) ×100 = 12%

The amount of yearly rent would be then increased by 12%

Monthly rent = $60
Yearly rent = 60×12 = $720
Increase by 12% = 720×1.12 = 806.4 ⇒ The value 1.12 is the multiplier, obtained from 100%+12%=112%=1.12

The monthly rent is 806.4÷12 = $67.20 which is an increase of $7.20 per month

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3 years ago

a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance it covers? i'll give brainliest to w

astraxan [27]

Answer:

nothing

Step-by-step explanation:

nothing

7 0

3 years ago

Read 2 more answers

Please someone help me...

laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \cot(6A) - \cot(2A) }$

<u>Using trigonometric </u><u>identities</u>

That's

<h3> $\cot(x) = \frac{1}{ \tan(x) }$ </h3>

<u>Rewrite the expression</u>

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \frac{1}{ \tan(6A) } } - \frac{1}{ \frac{1}{ \tan(2A) } }$

We have

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{ \tan(6A) \tan(2A) } }$ </h3>

<u>Rewrite the second fraction</u>

That's

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{ \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$ </h3>

Since they have the same denominator we can write the fraction as

$- \frac{1 + \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$

Using the identity

<h3> $\frac{x}{y} = \frac{1}{ \frac{y}{x} }$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $- \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{1 + \tan(6A) \tan(2A) } }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{ \tan(x) - \tan(y) }{1 + \tan(x) \tan(y) } = \tan(x - y)$ </h3>

<u>Rewrite the expression</u>

That's

<h3> $- \frac{1}{ \tan(2A -6A) }$ </h3>

Which is

<h3> $- \frac{1}{ \tan( - 4A) }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{1}{ \tan(x) } = \cot(x)$ </h3>

Rewrite the expression

That's

<h3> $- \cot( - 4A)$ </h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3> $- ( - \cot(4A) )$ </h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2> $\cot(4A)$ </h2>

As proven

Hope this helps you

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3 years ago

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which of the following are remote interior angles of 5? check all that apply. a 4 b 5 c 6 d 1 e 2 f 3

77julia77 [94]

From my research, the image supports the question. The exterior angle 5 can have up to 2 remote interior angles. Remote interior angles are the two angles inside the triangle that do not share a vertex with the external angle. From the choices, the two remote interior angles are 1 and 3. Among the choices, the correct answers are D and F.

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3 years ago