Answer:
10%
Step-by-step explanation:
i think
{ y ≥ 2x + 1; y > -2x - 3 } Unbound
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x = - 5 , x =
the values of x that make f(x) zero are the zeros
to find the zeros let f(x) = 0 , that is
3x² + 13x - 10 = 0
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 3 × - 10 = - 30 and sum = + 13
the factors are + 15 and - 2
use these factors to split the x- term
3x² + 15x - 2x - 10 = 0 ( factor the first/second and third/fourth terms )
3x(x + 5) - 2(x + 5) = 0 ← factor out (x + 5) from each term
(x + 5)(3x - 2) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
3x - 2 = 0 ⇒ 3x = 2 ⇒ x =
A' is everything what is not A
So:
A' = {9, 10, 11, 12, 13, 15, 16}
Number of ways it can happen: |A'| = 7
Total number of outcomes: |Ω| = 10
Probability of an event happening:
94.248 feet
1,131.0 inches
94′ 3″ feet and inches
28.727 meters
2,872.7 centimeters