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Rashid [163]
3 years ago
5

Bridget earns $5 per hour baby sitting if she baby sits from 5:00 p.m to 8:00 p.m how much will she earn

Mathematics
2 answers:
Nina [5.8K]3 years ago
5 0

Answer: 15$

Step-by-step explanation:

between 5 pm and 8 pm is 3 hours so 3x5=15$

masya89 [10]3 years ago
3 0

Answer:

$15

Step-by-step explanation:

8-5=3

3*5=15

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30 bags: each pound can make 5 bags (1/5) so 6 x 5 = 30
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The graph shows the amount of money Tanya earns from tutoring compared with the number of hours she works. Select the correct st
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B

Step-by-step explanation:

The graph (although it doesn't show it) is making points at every 20 (dollars) mark and also lines up to each hour mark, meaning that for every hour, Tanya makes 20 dollars.

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If 5k = -25, then 5k - 1 = -25 - 1<br> Segment proof
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6 0
3 years ago
Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the
Likurg_2 [28]

Answer:

(a)  moment generating function for X is \frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)

(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, P(X)=\frac{1}{6}

(a) Moment generating function can be written as M_{x}(t).

M_x(t)=\sum_{x=1}^{6} P(X=x)

M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}

M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)

(b) Now, find E(X) \text { and } E\((X^{2}) using moment generating function

M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)

M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)  

\Rightarrow E(X)=\frac{21}{6}

M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)

M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)

\Rightarrow E\left(X^{2}\right)=\frac{91}{6}  

Hence, (a) moment generating function for X is \frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right).

(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

6 0
3 years ago
How to solve? I prob know it I'm just stressing and panicking from all other stuff I gotta do
Nata [24]
Left one i think thats the one 
8 0
3 years ago
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