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3 years ago

Please help (connections academy chemistry)If you get it right I’ll give brainliest

Chemistry

2 answers:

liberstina [14]3 years ago

4 0

The answers are c c i hope this helps

Fiesta28 [93]3 years ago

3 0

A) 36.0 x 100 /2 = 1800 g Be

n = m / MM
stoichiometry 1:1
atomic mass of Be= 100 g/ mol

b) theoretical yield

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A neutral atom has 12 protons. In chemical bonding, which is the most likely charge of the ion?

Rina8888 [55]

It’s most likely A. 2+

6 0

3 years ago

If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

Darina [25.2K]

The question is incomplete, here is the complete question:

A bottle of rubbing alcohol having aqueous solution of alcohol contains 70% (v/v) alcohol. If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

<u>Answer:</u> The amount of water present in the given bottle of rubbing alcohol is 283.8 mL

<u>Explanation:</u>

We are given:

Volume of bottle of rubbing alcohol = 946 mL

70% (v/v) alcohol solution

This means that 70 mL of rubbing alcohol is present in 100 mL of solution

Amount of water present in solution = [100 - 70] = 30 mL

Applying unitary method:

In 100 mL of solution, the amount of water present is 30 mL

So, in 946 mL of solution, the amount of water present will be = $\frac{30}{100}\times 946=283.8mL$

Hence, the amount of water present in the given bottle of rubbing alcohol is 283.8 mL

4 0

3 years ago

What molecules have 5 carbon atoms and 12 hydrogen atoms

goldfiish [28.3K]

ANSWER

THE PENTANES

EXPLANATION

he word for5 in Greek is PENT like the 5 sided and 5 angled building in Wachington the PENTagon.

SO C5H12 IS PENTAND BECAUSE IT HAS NO DOUBLE BONDAS IT IS AN ALKANE

SO SO C5H12 IS PENT-ANE PENTANE AND THERE ARE MULTIPLE FORMS OF IT

4 0

3 years ago

3. If x electrons are needed to displace 108 g silver from a solution which contains Ag ions,

ss7ja [257]

Answer:

Choice A. $x$ electrons would be required for displacing $9\; \rm g$ of aluminum from a solution of $\rm Al^{3+}$ ions.

Assumption: by " $\rm Ag$ ions" the question meant $\rm Ag^{+}$ with a charge of $+1$ on each ion.

Explanation:

The question states that the relative atomic mass of $\rm Ag$ is $108$ . In other words, each mole of

Therefore, that $108\; \rm g\!$ of silver that were formed would contain $1\; \rm mol$ of silver atoms.

Metallic silver would precipitate out of this $\rm Ag^{+}$ solution only after these ions are turned into $\rm Ag$ atoms.

One $\rm Ag^{+}$ ion carries one unit of positive electrical charge. On the other hand, each $e^{-}$ carries one unit of negative electrical charge.

Therefore, each $\rm Ag^{+}\!$ ion will need to gain one electron to form a neutral $\rm Ag$ atom.

${\rm Ag^{+}}\; (aq) + e^{-} \to {\rm Ag}\; (s)$ .

At least $1\; \rm mol$ of electrons would be required to turn $1\; \rm mol\!$ of $\rm Ag^{+}$ ions into that $1\; \rm mol\!\!$ of silver atoms (which have a mass of $108\; \rm g\!$ .)

Hence, $x = 1\; \rm mol$ .

Unlike $\rm Ag^{+}$ ions, each aluminum ion $\rm Al^{3+}$ carries three units of positive electrical charge. That is three times the amount of charge on one $\rm Ag^{+}\!$ ion. Therefore, three electrons will be required to turn one $\rm Al^{3+}\!$ ion to an $\rm Al$ atom.

${\rm Al^{3+}}\; (aq) + 3\, e^{-} \to {\rm Al}\; (s)$

The question states that the relative atomic mass of $\rm Al$ is $27$ . Therefore, each mole of $\rm Al\!$ atoms would have a mass $27\; \rm g$ . There would be $\displaystyle \frac{9\; \rm g}{27\; \rm g \cdot mol^{-1}} = \frac{1}{3} \; \rm mol$ of atoms in that $9\; \rm g$ of $\rm Al\!\!$ .

It takes $3\; \rm mol$ of electrons to turn one mole of $\rm Al^{3+}$ ions to one mole of $\rm Al$ atoms. Hence, $\displaystyle \frac{1}{3}\times 3\; \rm mol = 1\; \rm mol$ of electrons would be required to produce that $\displaystyle \frac{1}{3}\; \rm mol$ of $\rm Al\!$ atoms (which has a mass of $9\; \rm g$ ) from $\rm Al^{3+}\!$ ions.