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Cloud [144]
4 years ago
11

Which element would release the most energy while adding an electron to a neutral atom in the gas phase? The choices are the fol

lowing: Na. . Al. . Br. . S
Chemistry
2 answers:
vfiekz [6]4 years ago
7 0

Answer: Br

Explanation:

Br:35:[Ar]3d^{10}4s^24p^5

Br^-:36:[Ar]3d^{10}4s^24p^6:[Kr]

Na:11:[Ne]3s^1

Na^-:12:[Ne]3s^2

Al:13:[Ne]3s^23p^1

Al^-:14:[Ne]3s^23p^2

S:16:[Ne]3s^23p^4

S^-:17:[Ne]3s^23p^5

As Bromine is short of only 1 electron to attain noble gas configuration, it will release energy as more stable species have less energy. Thus bromine would release most energy while adding an an electron to a neutral atom in the gas phase.

All other species Na, Al and S would not attain stable configuration on addition of electron and hence no energy would be released.

mel-nik [20]4 years ago
4 0
<span>Br <span>would release the most energy while adding an electron to a neutral atom in the gas phase.</span></span>

 

Bromine is a chemical element with symbol Br and atomic number 35. It is a halogen. The element was isolated independently by two chemists, Carl Jacob Löwig and Antoine Jérôme Balard.

 

The correct answer between all the choices given is the third choice. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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How many grams of aluminum sulfate: Al2(SO4)3 , would be formed if 250 g of H2SO4 react with aluminum? The reaction is: 2Al + 3H
NikAS [45]

Answer:

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

Explanation:

Step 1: Data given

Mass of H2SO4 = 250 grams

Molar mass H2SO4 = 98.08 g/mol

Step 2: The balanced equation

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

Step 3: Calculate moles H2SO4

Moles H2SO4 = mass H2SO4 / molar mass H2SO4

Moles H2SO4 = 250 grams / 98.08 g/mol

Moles H2SO5 = 2.55 moles

Step 4: Calculate moles Al2(SO4)3

For 2 moles Al we need 3 moles H2SO4 to produce 1 mol Al2(SO4)3 and 3 moles H2

For 2.55 moles H2SO4 we'll have 2.55/3 = 0.85 moles Al2(SO4)3

Step 5: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass

Mass Al2(SO4)3 = 0.85 moles * 342.15 g/mol

Mass  Al2(SO4)3 = 290.8 grams

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

7 0
4 years ago
Help mee, thank you. Science. Due tonight and I am very tired now :/
madreJ [45]
The first question it would would release the same amount.the answer to the second question would be the experimental group.
3 0
3 years ago
What is the symbol for molarity?
Romashka-Z-Leto [24]

The answer in chemistry is mol/L and altho it is represented by the symbol M usually.

3 0
3 years ago
Read 2 more answers
What is the rule of thumb for the activity trends of metals and nonmetals? Explain and give examples.
pentagon [3]

This for metal......the farther to the left the more reactive they are. Group 1 metals, which include sodium and potassium, are so highly reactive that they do not exist in nature by themselves


Thats non metals..........the farther to the right the more reactive they are *with the exception of group 18* which are the noble gases and do not react at all. The most reactive are group 17, which include fluorine and chlorine. These non-metals, like group 1, rarely exist by themselves because of their high reactivity.

5 0
4 years ago
How many moles of alumminum os needed to react woth 6.34 moles of fe3o4 in thereaction below? 8al + 3fe3o4_ 4al2o3 +9 fe
Alecsey [184]

 The moles of Al  that is needed  to react with  6.34   moles of Fe3O4  is  16.9 moles


<u><em> Explanation</em></u>

<em>  </em>8 Al+ 3Fe3O4 →  4 Al2O3 + 9Fe


use of  mole  ratio  of Al: fe3O4 to calculate  the  moles of  Al

The mole  ratio  of  Fe3O4 : Al  is 8:3  therefore the  moles of  Al =

6.34 moles x8/3 = 16.9 moles

7 0
3 years ago
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