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Cloud [144]
4 years ago
11

Which element would release the most energy while adding an electron to a neutral atom in the gas phase? The choices are the fol

lowing: Na. . Al. . Br. . S
Chemistry
2 answers:
vfiekz [6]4 years ago
7 0

Answer: Br

Explanation:

Br:35:[Ar]3d^{10}4s^24p^5

Br^-:36:[Ar]3d^{10}4s^24p^6:[Kr]

Na:11:[Ne]3s^1

Na^-:12:[Ne]3s^2

Al:13:[Ne]3s^23p^1

Al^-:14:[Ne]3s^23p^2

S:16:[Ne]3s^23p^4

S^-:17:[Ne]3s^23p^5

As Bromine is short of only 1 electron to attain noble gas configuration, it will release energy as more stable species have less energy. Thus bromine would release most energy while adding an an electron to a neutral atom in the gas phase.

All other species Na, Al and S would not attain stable configuration on addition of electron and hence no energy would be released.

mel-nik [20]4 years ago
4 0
<span>Br <span>would release the most energy while adding an electron to a neutral atom in the gas phase.</span></span>

 

Bromine is a chemical element with symbol Br and atomic number 35. It is a halogen. The element was isolated independently by two chemists, Carl Jacob Löwig and Antoine Jérôme Balard.

 

The correct answer between all the choices given is the third choice. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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What will be the volume of a gas sample at 337 K if its volume at 237 K is 12.0 L? Round your answer to 1 digit after the decima
oksano4ka [1.4K]

Answer:

17.1 L

Explanation:

V1/T1=V2/T2

V2=(V1*T2)/T1

V2= (12.0L * 337K)/237K

V2=17.1L

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4 years ago
Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1
FrozenT [24]

Answer: \Delta G_{rxn} for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the \Delta G_{rxn}, we use the formula:

\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}

For the given chemical reaction:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

We are given:

\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol

Now, to calculate \Delta G_{rxn}, we put the values in the above equation:

\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}

\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol

As, the value of \Delta G_{reaction} comes out to be positive, the reaction is said to be non-spontaneous reaction.

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3 years ago
Water waves are surface waves. The energy of the waves moves
horrorfan [7]

Answer:

Explanation:

<em>Waves are actually energy passing through the water, causing it to move in a circular motion. ... This phenomenon is a result of the wave's orbital motion being disturbed by the seafloor.</em>

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Read 2 more answers
A 1.0 L buffer solution is 0.300 M HC2H3O2 and 0.045 M LiC2H3O2. Which of the following actions will destroy the buffer?
zheka24 [161]

Answer:

b) Adding 0.075 moles of HCl

Explanation:

A buffer is defined as the aqueous mixture of a weak acid and its conjugate base or vice versa (Weak base with its conjugate acid).

The buffer of the problem is the acetic acid / lithium acetate.

The addition of any moles of the acid and the conjugate base will not destroy the buffer, just would change the pH of the buffer. Thus, a and c will not destroy the buffer.

The addition of an acid (HCl) or a base (NaOH), produce the following reactions:

HCl + LiC₂H₃O₂ → HC₂H₃O₂ + LiCl

<em>The acid reacts with the conjugate base to produce the weak acid.</em>

<em />

And:

NaOH + HC₂H₃O₂  →NaC₂H₃O₂ + H₂O

<em>The base reacts with the weak acid to produce conjugate base.</em>

<em />

As the buffer is 1.0L, the moles of the species of the buffer are:

HC₂H₃O₂ = 0.300 moles

LiC₂H₃O₂ = 0.045 moles

The reaction of HCl with LiC₂H₃O₂ consume all LiC₂H₃O₂ -<em>because there are an excess of moles of HCl that react with all </em>LiC₂H₃O₂-

As you will have just HC₂H₃O₂ after the reaction, the addition of b destroy the buffer.

In the other way, 0.0500 moles of NaOH react with the HC₂H₃O₂ but not consuming all HC₂H₃O₂, thus d doesn't destroy the buffer.

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kirza4 [7]
2) is the answer. graphite and diamonds possess the same molecular structes however the bonds and structures of diamonds are considerably stronger and more tightly packed respectively
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