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2 years ago

What molecules have 5 carbon atoms and 12 hydrogen atoms

Chemistry

1 answer:

goldfiish [28.3K]2 years ago

4 0

ANSWER

THE PENTANES

EXPLANATION

he word for5 in Greek is PENT like the 5 sided and 5 angled building in Wachington the PENTagon.

SO C5H12 IS PENTAND BECAUSE IT HAS NO DOUBLE BONDAS IT IS AN ALKANE

SO SO C5H12 IS PENT-ANE PENTANE AND THERE ARE MULTIPLE FORMS OF IT

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How many moles of potassium are contained in 449 g of<br> potassium?<br> pls help im so lost

e-lub [12.9K]

Answer:

449 (g K) / 39.1 (g/mol K) = 11.5 mol K

Explanation:

Potassium has atomic number 39.1

amount of K in 449g sample = 449/39.1 = 11.5 mol

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3 years ago

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Where did water become gas?

ASHA 777 [7]

Answer: Water becomes gas at D-E.

Explanation:
In the flat line D-E water is absorbing energy to become gas, and when the water is completely gas, the temperature will increase again therefore the line will rise up.

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3 years ago

Which set of numbers gives the correct possible values of l for n = 2

Paha777 [63]

HEY THERE!!

For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1) .

This means that the angular quantum number for a principal quantum number of 2 is equivalent to:

l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1

So the answer is 0, 1

HOPE IT HELPED YOU.

3 0

3 years ago

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In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2

valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

$\dfrac{80}{17}=4.706$

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

$\tt \dfrac{120}{32}=3.75$

Mol ratio of reactants(to find limiting reatants) :

$\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)$

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

$\tt \dfrac{6}{5}\times 3.75=4.5$

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

$\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%$

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3 years ago

Calculate the number of chlorine atoms that are present in 66.05 g of dichloromethane, ch2cl2. when you have the number, take it

Whitepunk [10]

From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of chlorine = 35.5 grams
Therefore,
molar mass of CH2Cl2 = 12 + 2(1) + 2(35.5) = 85 grams

number of moles = mass / molar mass
number of moles of CH2Cl2 = 66.05 / 85 = 0.777 moles

One mole of CH2Cl2 contains two moles of Cl and each chlorine mole has Avogadro's number of atoms in it.
Therefore,
number of chlorine atoms in 0.777 moles of CH2Cl2 can be calculated as follows:
number of atoms = 0.777 * 2 * 6.022 * 10^23 = 9.358 * 10^23 atoms

Now, we will take log base 10 for this number:
log (9.358 * 10^23) = 23.97119

5 0

3 years ago