So first, you have to remember the order of operations. That means that whatever is in the parentheses is what has to be done first
However, because one of the numbers in the parentheses is a variable and the other isn't, we can distribute instead
Therefore, 3(12+4x) distributes by multiplying the 3 into both numbers in the parentheses. So we get 36+12x
Now the equation is 20=8+36+12x
Now, bring all numbers without variables on the left side
20-8-36=8-8+36-36+12x
20-8-36=12x
Now simplify
20-8-36=12x
12-36=12x
-24=12x
Divide both sides by 12, and you get x=-2
Hope this helped!!! :D
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
Not sure either I need the question
First, we are going to find the vertex of our quadratic. Remember that to find the vertex

of a quadratic equation of the form

, we use the vertex formula

, and then, we evaluate our equation at

to find

.
We now from our quadratic that

and

, so lets use our formula:




Now we can evaluate our quadratic at 8 to find

:




So the vertex of our function is (8,-72)
Next, we are going to use the vertex to rewrite our quadratic equation:



The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.
We can conclude that:
The rewritten equation is

The x-coordinate of the minimum is 8
The picture is blank for me try it again