Answer:
D
Step-by-step explanation:
Volume of a cone is (1/3)πr^2h.
You have the necessary info, so just plug it in. (1/3)*π*(3/2)^2*(9/4)
Step-by-step explanation:
it's ur answers I hope it's helpful..
The <span>Pythagorean Theorem tells us that
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=%20a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
where c is the </span><span>hypotenuse and a and b are the other two sides. To solve for one of the shorter sides we need to rearrange:
![b=\sqrt{c^{2}-a^{2}}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7Bc%5E%7B2%7D-a%5E%7B2%7D%7D)
We can then substitute known values, and solve:
</span>
![b=\sqrt{10^{2}-8^{2}}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B10%5E%7B2%7D-8%5E%7B2%7D%7D)
![b=\sqrt{100-64}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B100-64%7D)
![b=\sqrt{36}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B36%7D)
According to law of cosines the length of RQ can be written as
.
Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.
A length of the triangle can be written as according to law of cosines if sides are given and one angle is ![a^{2} =b^{2} +c^{2} -2bccos(A)](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%3Db%5E%7B2%7D%20%2Bc%5E%7B2%7D%20-2bccos%28A%29)
We have to just put the values in the above equation.
as
.
p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.
Hence the side can be written as according to law of cosines if the angle is 39 degrees is as
.
Learn more about trigonometric functions at brainly.com/question/24349828
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Answer:
x=64°
Step-by-step explanation:
x=180-90-26 (angles on a str line)
=64°