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3 years ago

A regular hexagon is rotated about its center. By which angle could the hexagon be rotated so that its mapped onto itself?

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

Answer:

A regular hexagon can be mapped onto itself by a clockwise or counterclockwise rotation of 60°, 120°, or 180° about its center.

Hope this helps :)

vaieri [72.5K]3 years ago

7 0

answer is 60 degrees

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Consider quadrilateral BCEF inscribed in circle A. Diagonals EB and CF intersect at point D. Select all the statements that are

Elena L [17]

Answer:

$m\angle ECB+m\angle EFB=180$

$m\angle CDB\cong m\angle EDF$

$m\angle CDB+m\angle DCB+m\angle CBD=180 \degree$

Step-by-step explanation:

From the diagram, quadrilateral BCEF is a cyclic quadrilateral.

Opposite angles if a cyclic quadrilateral sum up to 180°

$m\angle ECB+m\angle EFB=180$

The diagonals intersect at D to form two pairs of vertical angles, and vertical angles are congruent.

$m\angle CDB\cong m\angle EDF$

Also sum of angles in triangle CBD is 180°.

$m\angle CDB+m\angle DCB+m\angle CBD=180 \degree$

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2 years ago

What is the vertex of the parabola? A. (-1,0) B. (0,-3) C. (1,-4) D. (3,0)

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d. (1,-4) is the answer

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3 years ago

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Answer:

24 units by 15 units

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120/5 = 24

75/5= 15

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3 years ago

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3 years ago

Find the values of the sine, cosine, and tangent for ZA. (TOP OF TRIANGLE IS (A))

Sloan [31]

$\bigstar\:{\underline{\sf{In\:right\:angled\:triangle\:ABC\::}}}\\\\$

AC = 7 m
BC = 4 m

⠀⠀⠀

$\bf{\dag}\:{\underline{\frak{By\:using\:Pythagoras\: Theorem,}}}\\\\$

$\star\:{\underline{\boxed{\frak{\purple{(Hypotenus)^2 = (Perpendicular)^2 + (Base)^2}}}}}\\\\\\ :\implies\sf (AB)^2 = (AC)^2 + (BC)^2\\\\\\ :\implies\sf (AB)^2 = (AB)^2 = (7)^2 = (4)^2\\\\\\ :\implies\sf (AB)^2 = 49 + 16\\\\\\ :\implies\sf (AB)^2 = 65\\\\\\ :\implies{\underline{\boxed{\pmb{\frak{AB = \sqrt{65}}}}}}\:\bigstar\\\\$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

☆ Now Let's find value of sin A, cos A and tan A,

⠀⠀⠀

sin A = Perpendicular/Hypotenus = $\sf \dfrac{4}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{4 \sqrt{65}}{65}}$

⠀⠀⠀

cos A = Base/Hypotenus = $\sf \dfrac{7}{\sqrt{65}} \times \dfrac{\sqrt{65}}{\sqrt{65}} = \pink{\dfrac{7 \sqrt{65}}{65}}$

⠀⠀⠀

tan A = Perpendicular/Base = ${\sf{\pink{\dfrac{4}{7}}}}$

⠀⠀⠀

$\therefore\:{\underline{\sf{Hence,\: {\pmb{Option\:A)}}\:{\sf{is\:correct}}.}}}$

4 0

2 years ago

A regular hexagon is rotated about its center. By which angle could the hexagon be rotated so that its mapped onto itself?​

A regular hexagon is rotated about its center. By which angle could the hexagon be rotated so that its mapped onto itself?