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bezimeni [28]
3 years ago
14

Write the relation as a set of ordered pairs.

Mathematics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

option B is the answer.

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What type of angle is each angle in this figure?
Naya [18.7K]
J= obtuse
K=right
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M=acute
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A/m=4g-h <br>need help with this problem ​
Olegator [25]

Answer:

a= m*(4g-h)

Step-by-step explanation:

hope it helps you

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A 11-inch candle burns down in 4 hours. At what rate does the candle burn, in inches per hour?
aliya0001 [1]

2.75 inches per hour

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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

\dfrac{A}{A'}=\dfrac{P^2}{P'^2}

We are given:

A=72 dm^2  , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. \dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}

on taking square root on both the side we get:

\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'

Now putting the value of P in equation (1) we obtain:

\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0
3 years ago
Please help!!!!!!!!!!!!.
kotykmax [81]

Answer:

The answer is D. You divide the shape into 3 rectangles.

Step-by-step explanation:

3 0
3 years ago
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