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Lubov Fominskaja [6]

2 years ago

11

Which of the following graphs represents the equation below?: -9x – 3y = -8

1 answer:

Mamont248 [21]2 years ago

7 0

It’s C! that’s the answer, hope it helps

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NASCAR driver Jimmy Johnson completed 200 laps as he crossed the finish line. From the start of the race to the finish line, is

Bond [772]

Answer:

B!!

Step-by-step explanation:

think its B im not sure

4 0

3 years ago

Read 2 more answers

The graph shows the height of a plant over time. What is the unit rate?

ipn [44]

The unit rate is 1/5. The plant grows 1 inch per 5 days.

5 0

2 years ago

What letter stays the same when reflected over the x-axis

valina [46]

When you reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate is transformed into its opposite (its sign is changed). If you forget the rules for reflections when graphing, simply fold your paper along the x-axis (the line of reflection) to see where the new figure will be located.p explanation:

6 0

2 years ago

Nancy wants to make a graph to show the relationship between the temperature of water, in degrees Celsius, and the time, in minu

ollegr [7]

The correct answer is B

8 0

2 years ago

) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

2 years ago