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Studentka2010 [4]
3 years ago
13

The diameter of the Moon is about 3476 kilometers the distance from the earth of the Moon is about 384,400 kilometers. about how

many moons could be lined up by row between earth and the moon? round to the nearest whole number
Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
111 moons could be lined up. 384400/3476
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Nadia has £5 to buy pencils and rulers. Pencils are 8p each. Rulers are 30p each. She says “I will buy 15 pencils. Then I will b
guapka [62]

Answer:

Total pencils: 17

Total rulers: 15

Step-by-step explanation:

"I will buy 15 pencils."

15 * 8p = £1.20

15 pencils

"Then I will buy as many rulers as possible."

£5 - £1.20 = £3.80

£3.80/30p = 12 remainder 20p

12 rulers

"With my change, I will buy more pencils.”

20p/8p = 2 remainder 4 p

2 pencils

Total pencils: 17

Total rulers: 15

3 0
3 years ago
Show if √5×√5×√8 is rational or irrational numbers​
kobusy [5.1K]
√5 x√5 x√8= √(5x5x8) = √200 = 10 √2
It’s an irrational number
8 0
2 years ago
Read 2 more answers
5
Daniel [21]

Answer:

Option A

..............................................................

7 0
3 years ago
Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim.The owner of a football team cla
nydimaria [60]

Answer:

Option D is correct.

Failure to reject the null hypothesis means that there is not sufficient evidence to support the claim that the mean attendance is greater than 694.

Step-by-step explanation:

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

It usually maintains that random chance is responsible for the outcome or results of any experimental study/hypothesis testing.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

It usually maintains that other than random chance, there are significant factors affecting the outcome or results of the experimental study/hypothesis testing.

For this question, the owner of a football team claims that the average attendance at games is over 694, and he is therefore justified in moving the team to a city with a larger stadium.

So, the null hypothesis would be that there isn't enough evidence to support the claim that the mean attendance is greater than 694.

That is, the mean isn't greater than 694; the mean is less than or equal to 694.

While the alternative hypothesis would be that there is sufficient evidence to support the claim that the mean attendance is greater than 694.

Mathematically,

The null hypothesis is represented as

H₀: μ₀ ≤ 694

The alternative hypothesis is represented as

Hₐ: μ₀ > 694

Failure to reject the null hypothesis means that the null hypothesis is true. Hence, the answer choice picked is the obvious correct answer.

Hope this Helps!!!

6 0
3 years ago
If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye
True [87]
First off, see  how much 8700 as principal, yields at 3% APR
that is \bf \qquad \textit{Simple Interest Earned}\\\\&#10;I = Prt\qquad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$8700\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;t=years\to &1&#10;\end{cases}

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

\bf \qquad \textit{Simple Interest Earned}\\\\&#10;I = Prt\quad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$8700\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;t=years\to &1&#10;\end{cases}&#10;\\\\\\&#10;\implies \boxed{?}\\\\&#10;-----------------------------\\\\&#10;\textit{how much to invest at 6\%?}&#10;\\\\\\&#10;

\bf \qquad \textit{Simple Interest Earned}\\\\&#10;(393-\boxed{?}) = Prt\quad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$\\&#10;r=rate\to 6\%\to \frac{6}{100}\to &0.06\\&#10;t=years\to &1&#10;\end{cases}&#10;\\\\\\&#10;\textit{solve for "P", to see how much should the Principal be}\\\\&#10;\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}
6 0
3 years ago
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