First pear Second pear probability
green (3/7)---------green (2/6) (3/7)*(2/6) = 1/7
---------red (4/6) (3/7) *(4/6) = 2/7
red (4/7)-------------green (3/6) (4/7)*(3/6) = 2/7
-------------red (3/6) (4/7)*(3/6) = 2/7
-------------------------
1/7 + 2/7 + 2/7 + 2/7 = 1
The probailities that two are green are: 1/7
The probabilities that one is green and the other is red are:2 /7 + 2/7 = 4/7
The probabilities that two are red are: 2/7
Answer:
3
Step-by-step explanation:
Using Pythagorean theorem, we can justify our answer.
if c^2 = a^2 + b^2 then triangle is right one,
if c^2 > a^2 + b^2 then triangle is obtuse and
if c^2 < a^2 + b^2 then triangle is acute triangle.
Here a=8, b=11 and c=16
Put these values in the equation
16^2 = 8 ^2 + 11^2
256 = 64 +121
256> 185
So here c^2 > a^2 + b^2 Which means triangle is obtuse triangle.
Answer: Obtuse Triangle
Answer:
The answer will be 12 please mark me as brainliest
Answer:
It is 5 or x>5
Step-by-step explanation:
