Answer:
21 and 26 totaling 47sticks
Step-by-step explanation:
Th number of sticks form an arithmetic progression
1, 6, 11, 16...
The nth term of an arithmetic progression is expressed as;
Tn = a+(n-1)d
a is the first term = 1
d is the common difference
d = 6-1 = 11-6 = 5
n is the number of terms
The next two terms are the fifth and sixth term
T5 = 1+(5-1)5
T5 = 1+4(5)
T5 = 1+20
T5 = 21
T6 = 1+(6-1)5
T6 = 1+5(5)
T6 = 1+25
T6 = 26
Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks
Add 10 on both sides
6x^2+12x+12=0.
Divide by 6 on both sides.
X^2+2x+2=0
Plug into quadratic formula
X=(-2 +\- (2^2-4•1•2))^1/2) /2•1
X=(-2 +\- (-4)^1/2)/2
X=(-2+\- 2i) /2
X=-1+\- I
X= -1 + i OR -1 - i
Answer:
2x + 2
Step-by-step explanation:
Simply distribute 2 to each of the terms (you multiply)
2(x + 1)
2x + 2
Answer:
i think just 2
Step-by-step explanation:
