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3 years ago

How to solve for 6x+3y=21 3x-7y=2

1 answer:

3 0

Hi there!

We can solve this equation by using the systems of equations.

We can do this by subtracting like terms from both equations using substitution.

First, let's find the value of y:

6x + 3y = 21
3y = -6x + 21
y = -2x + 7

Then, we should plug it into one of the equations:

3x - 7y = 2
3x - 7(-2x + 7) = 2
3x + 14x - 49 = 2
17x = 51
x = 3

Now, we solve for y by plugging the value of x into the equation:

3x - 7y = 2
3(3) - 7y = 2
9 - 7y = 2
-7y = -7
7y = 7
y = 1

There's your answers.

Hope this helps!

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3 years ago

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2 years ago

How would the expression x^2+27 be rewritten using sum of cubes?

nydimaria [60]

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3 years ago

The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics

liq [111]

Answer:

51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:

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The probability of passing one or the other is 51%.

<em>Additional comment</em>

We can also get there using the relation ...

P(A+B) = P(A) +P(B) -P(AB)

The union of A and B also includes their overlap:

P(A+B) = P(AB') +P(A'B) +P(AB)

In other words, the probability of interest is ...

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P(AB') +P(A'B) = 51%

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