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eimsori [14]
3 years ago
14

How to solve for 6x+3y=21 3x-7y=2

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0
Hi there!

We can solve this equation by using the systems of equations. 

We can do this by subtracting like terms from both equations using substitution. 

First, let's find the value of y:

6x + 3y = 21
3y = -6x + 21
y = -2x + 7

Then, we should plug it into one of the equations:

3x - 7y = 2
3x - 7(-2x + 7) = 2
3x + 14x - 49 = 2
17x = 51
x = 3

Now, we solve for y by plugging the value of x into the equation:

3x - 7y = 2
3(3) - 7y = 2
9 - 7y = 2
-7y = -7
7y = 7
y = 1

There's your answers.

Hope this helps!
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The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics
liq [111]

Answer:

  51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

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<em>Additional comment</em>

We can also get there using the relation ...

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