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2 years ago

For geometry:( will give brainist to the correct answer!!!

Mathematics

1 answer:

Pani-rosa [81]2 years ago

7 0

Answer:

y = ⅔x - 5

Step-by-step explanation:

The line that is parallel to 2x - 3y = 24, would have the same slope as the line, 2x - 3y = 24.

Rewrite;

2x - 3y = 24

-3y = -2x + 24

Divide both sides by -3

y = ⅔x - 8

Thus, the slope of 2x - 3y = 24 is ⅔.

Therefore the line that is parallel to 2x - 3y = 24, will have a slope (m) of ⅔.

Using point-slope form, we can generate an equation that passes through (-3, -7) and is parallel to 2x - 3y = 24.

Thus, substitute (a, b) = (-3, -7) and m = ⅔ into y - b = m(x - a)

Therefore:

y - (-7) = ⅔(x - (-3))

y + 7 = ⅔(x + 3)

Rewrite in slope-intercept form.

Multiply both sides by 3

3(y + 7) = 2(x + 3)

3y + 21 = 2x + 6

3y = 2x + 6 - 21

3y = 2x - 15

Divide both sides by 3

y = ⅔x - 5

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Answer:

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If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

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$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

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Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of s is also a prime factor of r.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

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2 years ago

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Ierofanga [76]

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