All categories

3 years ago

Solve for x: 0.2(2x-1)=0.2+0.08 A.1.4 B.5 C.2 D.0.3

Mathematics

1 answer:

Umnica [9.8K]3 years ago

8 0

Answer:

Step-by-step explanation:

0.4x-0.2=0.28

0.4x=.28+0.2

0.4x=0.48

You might be interested in

What is 3/5 x 4/7 And what is 9/10 x 5/18 What is 2,537 ÷ 25

Olin [163]

HOPE THIS WILL HELP U....:)

✌✌✌✌✌

7 0

2 years ago

Read 2 more answers

Y=3x+8 Y=-2x-2 can anyone help me with this ??

vivado [14]

Is it 2 different questions or just one?

6 0

2 years ago

Read 2 more answers

the triglyceride levels of residents of an assisted living facility are recordered the levels are normally distributed with a me

Svet_ta [14]

Answer:

Step-by-step explanation:

P(200<X<275)

P(200-200/50 <X< 275-200/50)

P(0/50 <X< 75/50)

P(0<X<1.5)

P(X<1.5) -P(X>0)

0.9332-0.5 = 0.4332

4 0

3 years ago

Read 2 more answers

what is the square root of 98 what is the square root of y to the 6th what is the square root of a to the 7th what is the square

Bogdan [553]

1. sqrt(98) = 7 sqrt(2)
2. sqrt(y^6) = y^3
3. sqrt(a^7) = a^7/2
4. sqrt(12x^3y^2) = 2xy sqrt(3x)
5. sqrt(36x^2y^4) = 6xy^2
6. sqrt(48ab^3) = 4b sqrt(3ab)
7. sqrt(10a^5b^2) = a^2b sqrt(10a)
8. sqrt(20x^3y^10 = 2xy^5 sqrt(5x)

7 0

3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

2 years ago

Read 2 more answers