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olga2289 [7]
3 years ago
8

Solve for x: 0.2(2x-1)=0.2+0.08 A.1.4 B.5 C.2 D.0.3

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

0.4x-0.2=0.28

0.4x=.28+0.2

0.4x=0.48

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Answer:

At 95% confidence level, the difference between the proportion of freshmen using steroids in Illinois and the proportion of seniors using steroids in Illinois is -7.01135×10⁻³ < \hat{p}_1-\hat{p}_2 < 1.237

Step-by-step explanation:

Here we are required to construct the 95% confidence interval of the difference between two proportions

The formula for the confidence interval of the difference between two proportions is as follows;

\hat{p}_1-\hat{p}_2\pm z^{*}\sqrt{\frac{\hat{p}_1\left (1-\hat{p}_1  \right )}{n_{1}}+\frac{\hat{p}_2\left (1-\hat{p}_2  \right )}{n_{2}}}

Where:

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n₂ = 1366

z_{\alpha /2} at 95% confidence level = 1.96

Plugging in the values, we have;

\frac{34}{1679}- \frac{24}{1366} \pm 1.96 \times \sqrt{\frac{ \frac{34}{1679}\left (1- \frac{34}{1679}\right )}{1679}+\frac{\frac{24}{1366} \left (1-\frac{24}{1366}   \right )}{1366}}

Which gives;

-7.01135×10⁻³ < \hat{p}_1-\hat{p}_2 < 1.237.

At 95% confidence level, the difference between the proportion of freshmen using steroids in Illinois and the proportion of seniors using steroids in Illinois = -7.01135×10⁻³ < \hat{p}_1-\hat{p}_2 < 1.237.

7 0
3 years ago
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