Answer:
Step-by-step explanation:
<h2>
</h2>
◇◆□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□◆◇
6A × B - 4C + 1A
6(2) × 4 - 4(3) + 1(2)
12 × 4 - 12 + 2
48 - 12 + 4
36 + 2
38
◇◆□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□■□◆◇
32. You love the 5t^-3 up to make it positive to get 7s5t^3
Answer:
Scale factor = 2 for C
Scale factor = 2 for D
Scale factor = 2 for B
Step-by-step explanation:
Shape C has the dimensions of 2 x 6
Shape A has the dimensions of 1 x 3
Shape C is exactly 2 times an englargement of A because:
multiply 1 (dimension of A) times 2 (scale factors) = 2 (dimension of C)
multiply 3 (dimension of A) times 2 (scale factors) = 6 (dimension of C)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Shape D has the dimensions of 2 x 6
Shape A has the demensions of 1 x 3
Shape D is exactly 2 times an englargement of A because (same as C):
multiply 1 (dimension of A) times 2 (scale factors) = 2 (dimension of D)
multiply 3 (dimension of A) times 2 (scale factors) = 6 (dimension of D)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Shape B has the dimensions of 3 x 9
Shape A has the demensions of 1 x 3
Shape B is exactly 3 times an englargement of A because:
multiply 1 (dimension of A) times 3 (scale factors) = 3 (dimension of B)
multiply 3 (dimension of A) times 3 (scale factors) = 9 (dimension of B)
Recall that the the vertical shifting of functions is associated with the numerical value that is added to the original one. A possitive value k will shift the function k units up, and a negativa value (or subtracting k) will move it vertically down k units.
If I understand correctly, you forgot to type an "x"in the original function f(x), which should read:
f(x) = 0.5 x
Correct?
The new graph is g(x) = 0.5 x - k which is obtained by shifting the original f(x) DOWN by 3 units.
In order to shift the graph of f(x) DOWN three units, we need to SUBTRACT 3 from f(x), leading to : 0.5 x - 3
Therefore, the value of "k"in the given g(x) = 0.5 x - k must be 3.
which agrees with the last option in your list (option D)
