All categories

3 years ago

Simplify: 6(2x-3)-(5x+7)

Mathematics

1 answer:

Gelneren [198K]3 years ago

5 0

First I would distribute the left part like so:
12x - 18 - (5x + 7)

Then I would distribute the right side like so: (I'm just distributing a negative sign)
12x - 18 - 5x - 7

Then I combine like terms like so: (12x and -5x)
7x - 18 - 7

Then I would combine the other like terms like so: (-18 and -7)
7x - 25

I hope that helps! Feel free to let me know if you have any questions! :3

- mathwizzard3

You might be interested in

What are the next two terms in the pattern 3,6,5,10,9,18,17...?

sleet_krkn [62]

the problem is a pattern that multiplies by two and subtracts one each time.

3x2=6 6-1=5 5x2=10 10-2=9 9x2=18 18-1=17 17x2=34 34-1=33

6 0

3 years ago

Read 2 more answers

Which solution finds the value of x in the triangle below?

forsale [732]

I didn't get it can you post a picture with it too?

5 0

3 years ago

Read 2 more answers

A student timed his drive to work each day for three days. The times are shown below:

cupoosta [38]

Answer:

20 minutes

Step-by-step explanation:

The mean, or average of a data set can be found by adding all the values together, and dividing by the number of values.

The data set is: 20 minutes, 22 minutes and 18 minutes

1. Add the values together

Add all the numbers in the set together.

Data set: 20, 22, 18

Add them: 20+22+18

2. Divide by the number of values

Count how many numbers are in the set.

In this set, there are 3 numbers.

Divide 60 by 3

60/3 =20

20 minutes

His mean time is 20 minutes.

8 0

3 years ago

Read 2 more answers

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea $d = \frac{a}{b}$ un número racional, donde $a, b \in \mathbb{R}$ y $b \neq 0$ , su opuesto es un número real $c = -\left(\frac{a}{b} \right)$ . En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, $c = d = 1$ . La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

$d' = d^{-n}$ y $c' = c^{-n}$

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

$d' = \left(\frac{a}{b} \right)^{-n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}$

$d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}$

$d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}$ y $c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[-\left(\frac{b}{a} \right)\right]^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = - \left(\frac{b}{a} \right)^{n}$

Puesto que $d' \neq c'$ , la proposición es falsa.

(c) El exponente es un negativo par.

Si $n$ es par, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left(\frac{b}{a} \right)^{n}$

Puesto que $d' = c'$ , la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

$d' = d^{n}$ y $c' = c^{n}$

$d' = \left(\frac{a}{b}\right)^{n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = - \left(\frac{a}{b} \right)^{n}$

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left(\frac{a}{b} \right)^{n}$

Si $n$ es par, entonces $d' = c'$ y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

3 0

3 years ago

The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous ran- dom variable with a cumulat

enyata [817]

Answer: 0.5507

Step-by-step explanation:

Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function

$F(x)= \begin{cases}0,& x$

Since , the waiting time is in hours , then we can write 12 minutes as $\dfrac{12}{60}$ hour i.e.0.2 hour.

Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-

$P(X$

Hence, the required probability = 0.5507

4 0

3 years ago