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QveST [7]
3 years ago
11

Jayne says that 0.45 is equal to 4/10. Is she correct? Explain.

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0
0.45 =  \dfrac{45}{100}

\dfrac{4}{10} =  \dfrac{4 \times 10}{10 \times 10} =  \dfrac{40}{100}

\dfrac{45}{100}  \neq  \dfrac{40}{100}

They are not the equal.
yKpoI14uk [10]3 years ago
4 0
No, 4/10 is equal to 0.40 and not 0.45 since 4/10 goes in tens.
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What is 324,650 rounded to the nearest thousands
solniwko [45]

The next bigger thousand is  325,000 .
The next smaller thousand is  324,000 .

324,650  is closer to  325,000  than it is to  324,000 .

So  325,000  is the nearest thousand.

6 0
3 years ago
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4 0
3 years ago
Read 2 more answers
Suppose that
Crazy boy [7]
<h3>Answers:</h3>
  • Absolute min = -6
  • Absolute max = 6

========================================================

Explanation:

The range of x values is -1 \le x \le 1 which means x = -1 is the smallest and x = 1 is the largest possible.

Similarly the smallest y value is y = -1 and the largest is y = 1.

----------

Plug in the smallest x and y value to get

f(x,y) = x+5y

f(-1,-1) = -1+5(-1)

f(-1,-1) = -6

Therefore, the absolute min is -6

----------

Now plug in the largest x and y values

f(x,y) = x+5y

f(1,1) = 1+5(1)

f(1,1) = 6

The absolute max is 6

8 0
2 years ago
Find the value of this expression if x = 6 and y = -1
asambeis [7]

Answer:

-\frac{6}{5}

Step-by-step explanation:

4 0
4 years ago
What is the probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words pe
mihalych1998 [28]

The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.

Given that the population mean, \mu = 90 wpm

The standard deviation of the population ,\sigma = 10

Sample size, n = 12

Sample mean, \bar x = 95

The reading rate of students follows the normal distribution.

Let z = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt n} }

        = \frac{95 - 90}{\frac{10}{\sqrt 12} }

        = 1.732

Probability that the mean reading exceeds 95 wpm = P(\bar x >95)

                                                                                       = P(z>1.732)

                                                                                       = 1- P(z<1.732)

                                                                                       = 0.4582

[The value 0.4582 found from the area under the normal curve using tables].

Learn more about Normal Distribution at brainly.com/question/27701525

#SPJ4

6 0
2 years ago
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